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Question

Physics Question on potential energy

The potential energy of 44 -particles each of mass 1kg1\,kg placed at the four vertices of a square of side length 1m1\,m is

A

+4.0G+ 4.0\, G

B

7.5G-7.5\,G

C

5.4G-5.4\,G

D

+6.3G+ 6.3 \,G

Answer

5.4G-5.4\,G

Explanation

Solution

Here, AB=BC=CD=DA=1mAB=BC=CD=DA=1\,m

BD=ACBD=AC
=12+12=\sqrt{1^{2}+1^{2}}
=2m=\sqrt{2}m
Total potential energy
+[G×1×1DA]+[G×1×1BD]+[G×1×1AC]+\left[\frac{-G\times1\times1}{DA}\right]+\left[\frac{-G\times1\times1}{BD}\right]+\left[\frac{-G\times1\times1}{AC}\right]
=4×[G×1×11]+2[G×1×12]=4\times\left[\frac{-G\times1\times1}{1}\right]+2\left[\frac{-G\times1\times1}{\sqrt{2}}\right]
=5.4G=-5.4\,G