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Question: The potential energy for a force field \(\left( 0 , \frac { \pi } { 4 } \right)\) is –...

The potential energy for a force field (0,π4)\left( 0 , \frac { \pi } { 4 } \right) is –

A

12\frac { 1 } { \sqrt { 2 } } (+ )

B

12\frac { 1 } { \sqrt { 2 } } ( + )

C

D

Answer

12\frac { 1 } { \sqrt { 2 } } ( + )

Explanation

Solution

Δ\vec { \Delta }U

= – cos (x + y)

= –cos (x + y) i^\hat { \mathbf { i } }δδy\frac { \delta } { \delta y } cos (x + y) δδz\frac { \delta } { \delta z } cos (x + y)

= sin (x + y) + sin (x + y)

x = 0, y = π4\frac { \pi } { 4 }

= sin π4\frac { \pi } { 4 } i^\hat { \mathbf { i } } + sin π4\frac { \pi } { 4 }

= i^2\frac { \hat { \mathrm { i } } } { \sqrt { 2 } } +