Question

The potential difference between points A & B in the given diagram is -

• A. 1 V
• B. 0.5 V
• C. 4 V
• D. 2 V

Answer 1

Answer: (D)

2 V

Answer 2

The circuit can be redrawn as

E_Net = $\frac{\frac{3}{1} + \frac{2}{1}}{\frac{1}{1} + \frac{1}{1}}$ = $\frac{5}{2}$;r_Net = ½

I**=**

$\frac{5/2}{(2 + 1/2) \times 10^{3}}$=$\frac{5/2}{5/2 \times 10^{3}}$

= 1 × 10^–3A ⇒∴ V_A – V_B = IR = 1 × 10^–3 ×2 ×10³ = 2V