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Question

Physics Question on Electric Current

The potential difference between points AA and BB is:

A

207V\frac{20}{7} V

B

407V\frac{40}{7} V

C

107V\frac{10}{7} V

D

zero

Answer

zero

Explanation

Solution

From the given figure, current through lower branch of resistances which are joined in series is
i1=104+3=107i_{1}=\frac{10}{4+3}=\frac{10}{7} amp