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Question

Question: The potential difference between \( A \) and \( B \) in the following situation is: ![](https://ww...

The potential difference between AA and BB in the following situation is:

Explanation

Solution

In this question, we need to find the potential difference between points AA and BB . To solve this, first select a point and assume the potential to be 0 V0{\text{ V}} at that point. After that, find out the current in all the branches of the circuit using Kirchhoff’s current law and then write down the voltage across each component of the circuit and then subtract the voltages between the required points to find the potential difference.

Complete step by step solution:
Let us assume the potential at point A be 0 V0{\text{ V}}
Let the current through DF{\text{DF}} branch be I1{I_1} and through FB{\text{FB}} branch be I2{I_2}

Now, applying Kirchhoff’s current law at point BB
As the total current entering a junction or node must be equal to the current leaving the node
Thus, I2=3+4{I_2} = 3 + 4
I2=7 A\Rightarrow {I_2} = 7{\text{ A}}
Similarly applying Kirchhoff’s current law at point FF we get,
5+I1=75 + {I_1} = 7
I1=2 A\Rightarrow {I_1} = 2{\text{ A}} towards the point FF
Now, since we got current through all the branches write down the potential drop across each component

Potential drop across the Ω{\text{2 }}\Omega resistor is 2×5=10 V2 \times 5 = 10{\text{ V}}
Potential drop across the battery should be 10 V10{\text{ V}}
Since point FF is connected to the negative terminal of battery potential at point FF is 0 V0{\text{ V}}
Current passing through Ω{\text{1 }}\Omega resistor is 7 A7{\text{ A}}
Potential drop across the Ω{\text{1 }}\Omega resistor will be 7 V7{\text{ V}}
Since current flows in a resistor from higher potential to lower potential, potential at point G{\text{G}} is 7 V- 7{\text{ V}}
Potential drop across battery must be 5 V{\text{5 V}}
Thus, VGVB=5{{\text{V}}_G} - {V_B} = 5
7VB=5- 7 - {V_B} = 5
VB=12 V\Rightarrow {V_B} = - 12{\text{ V}}
Potential difference between AA and BB is given by VAVB{{\text{V}}_A} - {V_B}
Substituting the values,
0(12)\Rightarrow 0 - \left( { - 12} \right)
VAVB=12 V\Rightarrow {{\text{V}}_A} - {V_B} = 12{\text{ V}}
The Potential difference between AA and BB is 12 V12{\text{ V}}.

Note:
To solve this type of question we can choose only one point at zero potential and must write all other potential in reference to it. We cannot take two points at zero potential thus one must choose the zero potential point such that the question can be solved easily.
In a resistor, current flows from higher potential to lower potential and in a battery, current flows from lower potential to higher potential. If the current flows in the opposite direction in a battery the battery is said to be charging.