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Question: The potential difference between A and B as shown in figure is <img src="https://cdn.pureessence.te...

The potential difference between A and B as shown in figure is

A

1 V

B

2 V

C

3 V

D

4 V

Answer

1 V

Explanation

Solution

:

Resistance of the upper arm CAD=2Ω+3Ω=5ΩCAD = 2\Omega + 3\Omega = 5\Omega

Resistance of the lower arm CBD=3Ω+2Ω=5ΩCBD = 3\Omega + 2\Omega = 5\Omega

As the resistance of both arms are equal, therefore same amount of current flows in both the arms.

Current through each arm CAD or CBD = 1 A

Potential difference across C and A is

VCVA=(2Ω)(1A)=2VV_{C} - V_{A} = (2\Omega)(1A) = 2V ….(i)

Potential difference across C and B is

VCVB=(3Ω)(1A)=3VV_{C} - V_{B} = (3\Omega)(1A) = 3V ….(ii)

Subtractin (i) from (ii), we get

VAVB=3V2V=1VV_{A} - V_{B} = 3V - 2V = 1V