Question

The potential difference applied to an X-ray tube is increased. As a result, in the emitted radiation

• A. the intensity increases
• B. the minimum wavelength increases
• C. the intensity remains unchanged
• D. the minimum wavelength decreases

Answer 1

Answer: (D)

the minimum wavelength decreases

Answer 2

$\lambda_m (inA) = \frac{12375}{V(in volt)}$
With increase in V, $\lambda_m$ will decrease. With decrease in
$\lambda_m$ energy of emitted photons will increase.
And hence intensity will increase even if number of photons
emitted per second are constant. Because intensity is basically
energy per unit area per unit time.