Question

The potential difference across the collector of a transistor, used in common emitter mode is $1.5\, V$, with the collector resistance of $3\, k\Omega$, the emitter current is $[\beta = 50]$

• A. $0.70\,mA$
• B. $0.49\,mA$
• C. $1.1\,mA$
• D. $1.9\,mA$

Answer 1

Answer: (B)

$0.49\,mA$

Answer 2

Here, $V_{CE} = 1.5\, V$ $R_c = 3\, k\Omega = 3 \times 10^3 \Omega; \beta = 50$ $\therefore I_{C} = \frac{V_{CE}}{R_{C}}$ $= \frac{1.5}{3 \times10^{3}}$ $= 0.5 \times10^{-3} A$ $I_{B} = \frac{I_{C}}{\beta}$ $= \frac{0.50\times10^{-3}}{50}$ $= 0.01 \times 10^{-3} A$ $I_{E} = I_{C} - I_{B}$ $= \left(0.50 - 0.01\right)\times 10^{-3}$ $= 0.49 \times10^{-3} A$ $= 0.49\, mA$