Question

The potential difference across the collector of a transistor, used in common emitter mode is $1.5V,$ with the collector resistance of 3 $k\Omega$ the emitter current is $\lbrack\beta = 50\rbrack$

• A. $0.70mA$
• B. $0.49mA$
• C. $1.1mA$
• D. $1.9mA$

Answer 1

Answer: (B)

$0.49mA$

Answer 2

: here, $V_{CE} = 1.5V$

$R_{C} = 3k\Omega = 3 \times 10^{3}\Omega;\beta = 50$

$\therefore I_{C} = \frac{V_{CE}}{R_{C}} = \frac{1.5}{3 \times 10^{3}} = 0.5 \times 10^{- 3}A$

$I_{B} = \frac{I_{C}}{\beta} = \frac{0.50 \times 10^{- 3}}{50} = 0.01 \times 10^{- 3}A$

}{= 0.49 \times 10^{- 3}A = 0.49mA}$$