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Question

Question: The potential at a point, due to a positive charge of \(100\mu C\) at a distance of 9m, is...

The potential at a point, due to a positive charge of 100μC100\mu C at a distance of 9m, is

A

10410^{4}V

B

10510^{5}V

C

10610^{6}V

D

10710^{7}V

Answer

10510^{5}V

Explanation

Solution

By using V=9×109×Qr=9×109×100×1069=105VV = 9 \times 10^{9} \times \frac{Q}{r} = 9 \times 10^{9} \times \frac{100 \times 10^{- 6}}{9} = 10^{5}V