Question

The potential at a point due to a charge of $5 \times 10^{- 7}C$ located 10 cm away is.

• A. $3.5 \times 10^{5}V$
• B. $3.5 \times 10^{4}V$
• C. $4.5 \times 10^{4}V$
• D. $4.5 \times 10^{5}V$

Answer 1

Answer: (C)

$4.5 \times 10^{4}V$

Answer 2

: Here, $q = 5 \times 10^{- 7}C,r = 10cm = 0.1m$

Potential,$V = \frac{1}{4\pi\varepsilon_{o}}\frac{q}{r} = \frac{9 \times 10^{o} \times 5 \times 10^{- 7}}{0.1} = 4.5 \times 10^{4}V$