Question

The possible value of $\mathcal{l}$ and m for the last electron in the Cl– ion are :

• A. 1 and 2
• B. 2 and + 1
• C. 3 and – 1
• D. 1 and – 1

Answer 1

Answer: (D)

1 and – 1

Answer 2

Cl17– : [Ne] 3s2 3p6.

Last electron enters 3p orbital.

$\therefore$ $\mathcal{l}\text{ = 1 and m = 1, 0, -1.}$