Question

The positive value of $\Delta S$ indicates that:
A. the system becomes less disordered
B. the system becomes more disordered
C. the system is in equilibrium position
D. the system tends to reach at equilibrium position

Answer 1

$\Delta S$ is a change of entropy. Entropy is a state function of any system. It is only depending upon the initial and final state of the system throughout a process, but does not depend upon the pathway of the process.

Complete step by step answer:
This concept of entropy is used to measure the spontaneity of any process or change of the system. According to the second law of thermodynamics for an isolated system (no exchange of heat or mass with the surroundings) the reversible process always proceeds to increase the entropy. Therefore, from this law it is concluded that any process would be spontaneous if the entropy is increasing though that process. For example: melting of ice is a spontaneous process, as due to the melting of ice entropy of the system increases.
When the entropy of the final state of any process is higher than the initial state, the change of entropy. I.e. $\Delta S$ becomes positive. And when the entropy of the final state of any process is lower than the initial state, the change of entropy. I.e. $\Delta S$ becomes negative.
Now the change of entropy basically indicates the change of disorders of randomness of the system.
So, if change of entropy( $\Delta S$ ) is positive then the system becomes more disordered.

So, the correct option is B.

Note:
Enthalpy is also a state function. It is only depending upon the initial and final state of the system throughout a process, but does not depend upon the pathway of the process. The change of enthalpy is a measure of heat of the reaction. And if $\Delta H$ is positive then that process is endothermic and if $\Delta H$ is negative then that process is exothermic.