Question

The positive charged ball is suspended by thread of silk. If we place a positive charge ${{q}_{0}}$ at one point and measure the $F/{{q}_{0}},$ then this can say that electric field E

• A. $>\frac{F}{{{q}_{0}}}$
• B. $=\frac{F}{{{q}_{0}}}$
• C. $=\frac{F}{{{q}_{0}}}$
• D. $Can't\,be\,measured$

Answer 1

Answer: (A)

$>\frac{F}{{{q}_{0}}}$

Answer 2

Electric field, $E>\frac{F}{{{q}_{0}}}$