Question
Question: The position vectors of two points P and Q are \(3\mathbf{i} + \mathbf{j} + 2\mathbf{k}\) and \(\mat...
The position vectors of two points P and Q are 3i+j+2k and i−2j−4k respectively. The equation of the plane through Q and perpendicular to PQ is
A
r.(2i+3j+6k)=28
B
r.(2i+3j+6k)=32
C
r.(2i+3j+6k)+28=0
D
None of these
Answer
r.(2i+3j+6k)+28=0
Explanation
Solution
The required plane is {r−(i−2j−4k)}.PQ→=0.