Solveeit Logo

Question

Physics Question on types of forces

The position-time graph of a particle of mass 4kg4 \,kg is shown in the figure. Calculate the impulse (in MKSMKS units) at time t=0t = 0 and t=6secondst = 6 \,seconds respectively

A

+6.31+6.31 and 6.31- 6.31

B

+3.33+3.33 and 3.33-3.33

C

+6.33+6.33 and 6.33-6.33

D

+3.25+3.25 and 3.25-3.25

Answer

+3.33+3.33 and 3.33-3.33

Explanation

Solution

The position-time graph gives the velocity

According to this graph, velocity at t=6st = 6 \,s
v=56m/sv = \frac{5}{6} m/s
Impulse == Change in momentum
=m1v2m2v1= m_1v_2 - m_2v_1
=4×5/64×0= 4\times 5/6 - 4 \times 0
=20/6=3.33= 20/6 = 3.33
So option (b) is correct.