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Question: The position-time graph of a body of mass 2 kg is as shown in figure. What is the impulse on the bod...

The position-time graph of a body of mass 2 kg is as shown in figure. What is the impulse on the body at t 4 s?

A

23kgms−1\frac{2}{3}kgms - 1

B

−23kgms−1- \frac{2}{3}kgms^{- 1}

C

32kgms−1\frac{3}{2}kgms^{- 1}

D

−32kgms−1- \frac{3}{2}kgms^{- 1}

Answer

−32kgms−1- \frac{3}{2}kgms^{- 1}

Explanation

Solution

At t=4s the body has constant velocity

u=34ms−1u = \frac{3}{4}ms^{- 1}

After t=4st = 4sthe body is at rest i.e. v= 0

∴\thereforeImpulse =m(v−u)= m(v - u)

=2kg(0−34ms−1)=−34kgms−1= 2kg(0 - \frac{3}{4}ms^{- 1}) = - \frac{3}{4}kgms^{- 1}