Question

The position of centre of mass far of the solid body shown in fig. is- [mass of part of body below X is 2m and above X –Z plane is m)

• A. –$\frac{R}{12}$
• B. – $\frac{5R}{24}$
• C. –$\frac{3R}{24}$
• D. None

Answer 1

Answer: (B)

– $\frac{5R}{24}$

Answer 2

X_cm = 0

Y_cm = $\frac{m \times \frac{3R}{8} - 2m \times \frac{2R}{4}}{m + 2m}$Y_cm= $\frac{\frac{3R}{8} - R}{3}$ = – $\frac{5R}{24}$