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Question

Physics Question on speed and velocity

The position of an object moving along xx-axis is given by x=a+bt2x = a + bt^2, where a=8.5ma = 8.5 \,m and b=2.5ms2b = 2.5\, m \,s^{-2} and tt is measured in seconds. The instantaneous velocity of the object at t=2st = 2\,s is

A

5ms15\,m\,s^{-1}

B

10ms110\,m\,s^{-1}

C

15ms115\,m\,s^{-1}

D

20ms120\,m\,s^{-1}

Answer

10ms110\,m\,s^{-1}

Explanation

Solution

Here, x=a+bt2x = a + bt^2 Where, a=8.5ma = 8.5\, m and b=2.5ms2b = 2.5\, m\, s^{-2} Velocity, v=dxdt=ddt(a+bt2)=2btv=\frac{dx}{dt}=\frac{d}{dt}\left(a+bt^{2}\right)=2bt At t=2st=2\,s, v=2(2.5ms2)(2s)=10ms1v = 2\left(2.5\, m\, s^{-2}\right)\left(2 \,s\right) = 10\, m\, s^{-1}