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Question

Question: The position of a particle is given by \(\overrightarrow{r} = 3t\widehat{i} + 2t\widehat{j} + 5\wide...

The position of a particle is given by r=3ti^+2tj^+5k^\overrightarrow{r} = 3t\widehat{i} + 2t\widehat{j} + 5\widehat{k}, where t is in seconds and the coefficients have the proper units for r\overrightarrow{r}to be in metres. The acceleration of the particle at t = 1 s is

A

2j^ms22\widehat{j}ms^{- 2}

B

2j^ms2- 2\widehat{j}ms^{- 2}

C

4j^ms24\widehat{j}ms^{- 2}

D

4j^ms2- 4\widehat{j}ms^{- 2}

Answer

4j^ms24\widehat{j}ms^{- 2}

Explanation

Solution

For the questions number 31

v=3i^+4tj^ms1\overset{\rightarrow}{v} = 3\widehat{i} + 4t\widehat{j}ms^{- 1}

\thereforeAccelerations , a=dvdt=4j^ms2\overrightarrow{a} = \frac{d\overset{\rightarrow}{v}}{dt} = 4\widehat{j}ms^{- 2}

Accelerations of the particle remains constant at all times.