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Question: The population of the bacteria colony starts at 100 and grows by \[30\% \] per hour. A.Find the f...

The population of the bacteria colony starts at 100 and grows by 30%30\% per hour.
A.Find the formula for the number of bacteria, P, after t hours.
B.What is the doubling time of this population; that is, how long does it take the population to double in size?

Explanation

Solution

Hint : To solve this question, we need to use the concept of exponential growth. The exponential growth occurs when the growth rate of the value of a mathematical function is proportional to the function’s current value, resulting in its growth with time being an exponential function. We can also say that when the growth of a function increases rapidly in relation to the increase in the total number, then it is exponential.
Formula used:
Systems that experiences exponential growth increase according to the mathematical model:
P=P0ektP = {P_0}{e^{kt}}
Where, P0{P_0} represents the initial state of the system and kk is a constant, called the growth constant.

Complete step by step solution:
We are given that the bacteria colony starts at 100 and grows by 30%30\% per hour.
Therefore, P0=100{P_0} = 100 and k=0.3k = 0.3 .
By using the formula P=P0ektP = {P_0}{e^{kt}} , we can say that P=100e0.3tP = 100{e^{0.3t}} .
Thus, the answer for our first question is: the formula for the number of bacteria, P, after t hours is: P=100e0.3tP = 100{e^{0.3t}} .
We also know that the continuous growth rate is nothing but the growth constant.
Therefore, the answer to the third question is: the continuous growth rate for the colony is 0.30.3 .
Now, for the second question, we have to find the doubling time.
Therefore, P=2P0=200P = 2{P_0} = 200 . Putting this value into the main equation, we will get

200=100e0.3t 2=e0.3t   200 = 100{e^{0.3t}} \\\ \Rightarrow 2 = {e^{0.3t}} \;

Now, we will take logarithms on both the sides.

ln2=lne0.3t ln2=0.3tlne 0.693=0.3t t=2.31hours   \Rightarrow \ln 2 = \ln {e^{0.3t}} \\\ \Rightarrow \ln 2 = 0.3t\ln e \\\ \Rightarrow 0.693 = 0.3t \\\ \Rightarrow t = 2.31 \,hours \;

Thus, our second answer is: The doubling time of the population is 2.31hours2.31 \, hours .

Note : Here, in this question, we have used two rules of the logarithms. First, the exponent rule: lnab=blna\ln {a^b} = b\ln a . And the second rule which states that the logarithm of the number with the same base is 1 that is lne=logee=1\ln e = {\log _e}e = 1 .