Question
Question: The polynomial (ax<sup>2</sup> + bx + c) (ax<sup>2</sup> –dx –c); ac ¹ 0 has-...
The polynomial (ax2 + bx + c) (ax2 –dx –c); ac ¹ 0 has-
A
Four real zeros
B
At least two real zeros
C
At most two real zeros
D
None of the above
Answer
At least two real zeros
Explanation
Solution
D1 = b2 –4ac and D2 = a2 + 4ac
D1 + D2 = b2 + d2 > 0
So at least of D1 and D2 is positive.
Hence polynomial has at least two real zeros.