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Question: The polynomial (ax<sup>2</sup> + bx + c) (ax<sup>2</sup> –dx –c); ac ¹ 0 has-...

The polynomial (ax2 + bx + c) (ax2 –dx –c); ac ¹ 0 has-

A

Four real zeros

B

At least two real zeros

C

At most two real zeros

D

None of the above

Answer

At least two real zeros

Explanation

Solution

D1 = b2 –4ac and D2 = a2 + 4ac

D1 + D2 = b2 + d2 > 0

So at least of D1 and D2 is positive.

Hence polynomial has at least two real zeros.