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Question

Question: The polar of the point \(\left( 5 , - \frac { 1 } { 2 } \right)\) with respect to circle \(( x - 2...

The polar of the point (5,12)\left( 5 , - \frac { 1 } { 2 } \right) with respect to circle (x2)2+y2=4( x - 2 ) ^ { 2 } + y ^ { 2 } = 4 is

A

5x10y+2=05 x - 10 y + 2 = 0

B

6xy20=06 x - y - 20 = 0

C

10xy10=010 x - y - 10 = 0

D

x10y2=0x - 10 y - 2 = 0

Answer

6xy20=06 x - y - 20 = 0

Explanation

Solution

The polar of the point (5,12)\left( 5 , - \frac { 1 } { 2 } \right) is

3xy210=06xy20=0\Rightarrow 3 x - \frac { y } { 2 } - 10 = 0 \Rightarrow 6 x - y - 20 = 0