Question

The polar coordinates of (2, –2) will be–

• A. $\left( 2\sqrt{2},\frac{\pi}{4} \right)$
• B. $\left( - 2\sqrt{2},\frac{\pi}{4} \right)$
• C. $\left( 2\sqrt{2},\frac{3\pi}{4} \right)$
• D. $\left( - 2\sqrt{2},\frac{3\pi}{4} \right)$

Answer 1

Answer: (D)

$\left( - 2\sqrt{2},\frac{3\pi}{4} \right)$

Answer 2

r = $\sqrt{x^{2} + y^{2}}$ = $\sqrt{4 + 4}$ = $2\sqrt{2}$

a = tan^–1 $\left( \frac{2}{2} \right)$ = $\frac{\pi}{4}$

(+2, –2) lies in IV quad.

\ q = – a Ž q = $- \frac{\pi}{4}$

$\left( 2\sqrt{2}, - \frac{\pi}{4} \right)$ or $\left( - 2\sqrt{2},\frac{3\pi}{4} \right)$