The polar co-ordinates of (–1, (\sqrt{3})) is- | MATH - SYSTEM OF CO-ORDINATES, DISTANCE BETWEEN | SolveeIt

The polar co-ordinates of (–1, $\sqrt{3}$ ) is-

$\left( 2,\frac{\pi}{6} \right)$

$\left( 2,\frac{\pi}{3} \right)$

$\left( 2,\frac{2\pi}{3} \right)$

$\left( - 2,\frac{2\pi}{3} \right)$

Answer

$\left( 2,\frac{2\pi}{3} \right)$

Explanation

r = $\sqrt{x^{2} + y^{2}}$

r = $\sqrt{1 + 3}$ = 2

a = tan^–1 $\frac{|y|}{|x|}$

a = tan^–1 ( $\sqrt{3}$ = $\frac{\pi}{3}$ –1, $\sqrt{3}$ ) lies in II quad.

\ q = p – a = p – $\frac{\pi}{3}$ = $\frac{2\pi}{3}$

$\left( 2,\frac{2\pi}{3} \right)$

Question: The polar co-ordinates of (–1, \(\sqrt{3}\)) is-...