The pointegrals on the curve (\frac{x^2}{9} + \frac{y^2}{16}... | Mathematics | SolveeIt | Solveeit

Today, August 18

Question

The points on the curve $\frac{x^2}{9} + \frac{y^2}{16} = 1$ at which the tangents are parallel to x-axis:

A

(0,4), (0,-4)

B

(0, 0), (0,-4)

C

(4, 0), (-4, 0)

D

(0, 0), (0, 4)

Answer

(0,4), (0,-4)

Explanation

Solution

The correct option is (A): (0,4), (0,-4)