Question

The points of intersection of the line $a x+b y=0,(a \neq b)$ and the circle $x^2+y^2-2 x=0$ are $A (\alpha, 0)$ and $B (1, \beta)$ The image of the circle with $AB$ as a diameter in the line $x+y+2=0$ is :

• A. $x^2+y^2+3 x+3 y+4=0$
• B. $x^2+y^2+5 x+5 y+12=0$
• C. $x^2+y^2+3 x+5 y+8=0$
• D. $x^2+y^2-5 x-5 y+12=0$

Answer 1

Answer: (B)

$x^2+y^2+5 x+5 y+12=0$

Answer 2

Only possibility a=0,�=1
? equation of circle x2+y2-x-y=0
Image of circle in x+y+2=0 is
x2+y2+5x+5y+12=0