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Question: The points \(\left( x_{1},y_{1} \right)\)and \(\left( x_{2},y_{2} \right)\mspace{6mu}\mspace{6mu} on...

The points (x1,y1)\left( x_{1},y_{1} \right)and (x2,y2)6mu6muon6muy2=4x\left( x_{2},y_{2} \right)\mspace{6mu}\mspace{6mu} on\mspace{6mu} y^{2} = 4x and the point (1, 0) are collinear. Then x1x2+y1y2=x_{1}x_{2} + y_{1}y_{2} =

A

-1

B

-2

C

-3

D

–5

Answer

-3

Explanation

Solution

If t1, t2 are the extremities of a focal chord, then t1.t2 =-1

Since (1, 0) is the focus of y2 = 4x.

⇒ (x1, y1) and (x2,y2) are the extremities of focal chord.

⇒ x1x2 + y1y2 = at12.at22+2at1.2at2at_{1}^{2}.at_{2}^{2} + 2at_{1}.2at_{2}

= a2(t1t2)2+4a2(t1t2)a^{2}(t_{1}t_{2})^{2} + 4a^{2}(t_{1}t_{2})

= a24a2=3a2=3a^{2} - 4a^{2} = - 3a^{2} = - 3