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Question: The points A (0, 0), B (3, 0) and C(0, 4) are mid-points of sides of triangle then the area of D is-...

The points A (0, 0), B (3, 0) and C(0, 4) are mid-points of sides of triangle then the area of D is-

A

24 sq. units

B

48 sq. units

C

12 sq. units

D

36 sq. units

Answer

24 sq. units

Explanation

Solution

Area of D = 4. DABC

= 4. (12.3.4)\left( \frac{1}{2}.3.4 \right)

= 24 sq. units.