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Question: The points (5, 2, 4), (6, –1, 2) and (8, –7, k) are collinear, if k is equal to...

The points (5, 2, 4), (6, –1, 2) and (8, –7, k) are collinear, if k is equal to

A

–2

B

2

C

3

D

–1

Answer

–2

Explanation

Solution

If given points are collinear, then

x1x2x2x3=y1y2y2y3=z1z2z2z3\frac { x _ { 1 } - x _ { 2 } } { x _ { 2 } - x _ { 3 } } = \frac { y _ { 1 } - y _ { 2 } } { y _ { 2 } - y _ { 3 } } = \frac { z _ { 1 } - z _ { 2 } } { z _ { 2 } - z _ { 3 } }

5668=2+11+7=422k\frac { 5 - 6 } { 6 - 8 } = \frac { 2 + 1 } { - 1 + 7 } = \frac { 4 - 2 } { 2 - k }

12=36=22k\frac { - 1 } { - 2 } = \frac { 3 } { 6 } = \frac { 2 } { 2 - k }12=22k\frac { 1 } { 2 } = \frac { 2 } { 2 - k }

k=2k = - 2