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Question

Question: The points (3a, 0), (0, 3b) and (a, 2b) are....

The points (3a, 0), (0, 3b) and (a, 2b) are.

A

Vertices of an equilateral triangle

B

Vertices of an isosceles triangle

C

Vertices of a right angled isosceles triangle

D

Collinear

Answer

Collinear

Explanation

Solution

l1=(3a)2+(3b)2=3a2+b2l _ { 1 } = \sqrt { ( 3 a ) ^ { 2 } + ( 3 b ) ^ { 2 } } = 3 \sqrt { a ^ { 2 } + b ^ { 2 } }

l2=a2+b2=a2+b2l _ { 2 } = \sqrt { a ^ { 2 } + b ^ { 2 } } = \sqrt { a ^ { 2 } + b ^ { 2 } }

l3=(2a)2+(2b)2=2a2+b2l _ { 3 } = \sqrt { ( 2 a ) ^ { 2 } + ( 2 b ) ^ { 2 } } = 2 \sqrt { a ^ { 2 } + b ^ { 2 } } l1=l2+l3\Rightarrow l _ { 1 } = l _ { 2 } + l _ { 3 }

Hence the points are collinear.