Question
Mathematics Question on Quadratic Equations
The point which does not belong to the feasible region of the LPP:Minimize: Z=60x+10ysubject to 3x+y≥182x+2y≥12x+2y≥10x,y≥0 is:
A
(A) (0,8)
B
(B) (4,2)
C
(C) (6,2)
D
(D) (10,0)
Answer
(B) (4,2)
Explanation
Solution
Explanation:
Given:Minimize: Z=60x+10ysubject to 3x+y≥182x+2y≥12x+2y≥10x,y≥0We test whether the inequalitiies are satisfied or not (0,8),3(0)+8≥88≥8 is true.2(0)+2(8)=16≥12 is true. 0+2(8)=16≥10 is true.∴(0,8) is in the feasible region.(4,2),3(4)+2=14≥82(4)+2(2)=16≥124+2(2)=8≥10 is not true∴(4,2) is not a point in the feasible regionHence, the correct option is (B).