Question
Question: The point on the line \(\frac{x - 2}{1} = \frac{y + 3}{- 2} = \frac{z + 5}{- 2}\) at a distance of 6...
The point on the line 1x−2=−2y+3=−2z+5 at a distance of 6 units from the point (2, –3, – 5) –
A
(3, –5, –3)
B
(4, –7, –9)
C
(0, 2, –1)
D
(–3, 5, 3)
Answer
(4, –7, –9)
Explanation
Solution
Let point is P(l + 2, –2l – 3, –2l – 5)
\ distance of P form Q (2, –3, – 5) is 6.
\ PQ = 6
̃ PQ2 = 36
(l + 2 – 2)2 + (–2l – 3 + 3)2 + (–2l – 5 + 5)2 = 36
l2 + 4l2 + 4l2 = 36
̃ l = ± 2
\ P º (4, –7, –9) or P º (0, 1, –1)