Question

The point on the curve y = x² – 3x + 2 where tangent is perpendicular to y = x is –

• A. (0, 2)
• B. (1, 0)
• C. (–1, 6)
• D. (2, –2)

Answer 1

Answer: (B)

(1, 0)

Answer 2

$\frac{dy}{dx}$ = 2x – 3 & slope of given line = 1

Ž line ^ tangent

$\left( \frac{dy}{dx} \right)$ × 1 = – 1

Ž 2x – 3 = – 1

Ž x = 1, y = 0

\ point (1, 0)