Question

The point of intersection of tangent to the curve y = x⁴ at

(1, 1) with the normal to the same curve at (–1, 1) is –

• A. $\left( \frac{17}{15},\frac{13}{15} \right)$
• B. $\left( \frac{7}{5},\frac{3}{5} \right)$
• C. $\left( \frac{17}{15},\frac{23}{15} \right)$
• D. Does not exist

Answer 1

Answer: (C)

$\left( \frac{17}{15},\frac{23}{15} \right)$

Answer 2

$\frac{dy}{dx}$ = 4x³ equation of tangent is y –1 = 4(x – 1)

Equation of normal is y – 1 = (1/4) (x + 1)