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Question

Mathematics Question on Straight lines

The point (4, 1) undergoes the following three transformations successively I. Reflection about the line y = x. II. Transformation through a distance 2 units along the positive direction of X-axis. III. Rotation through an angle π4\frac{\pi}{4} about the origin in the counter clockwise direction. Then, the final position of the point is given by the coordinates

A

(12,72)\Bigg(\frac{1}{\sqrt{2}},\frac{7}{\sqrt{2}}\Bigg)

B

(2,72)(-\sqrt{2}, 7\sqrt{2})

C

(12,72)\Bigg(-\frac{1}{\sqrt{2}},\frac{7}{\sqrt{2}}\Bigg)

D

(2,72)(\sqrt{2}, 7\sqrt{2})

Answer

(12,72)\Bigg(-\frac{1}{\sqrt{2}},\frac{7}{\sqrt{2}}\Bigg)

Explanation

Solution

Let B, C, D be the position of the point A (4,1) after the three operations I, II and III, respectively. Then, B is (1, 4), C(1 + 2,4) i.e. (3, 4). The point D is obtained from C by rotating the coordinate axes through an angle π/4\pi/4 in anti-clockwise direction. Therefore, the coordinates of D are given by X=3cosπ24sinπ4=12X =3cos \frac{\pi}{2}-4 sin \frac{\pi}{4}=-\frac{-1}{\sqrt{2}} and Y=3sinπ4+4cosπ4=72Y=3 sin \frac{\pi}{4}+4 cos\frac{\pi}{4}=\frac{7}{\sqrt{2}} \therefore Coordinates of D are (12,72).\Bigg(-\frac{1}{\sqrt{2}},\frac{7}{\sqrt{2}}\Bigg).