Question

The point $(2t^2 + 2t + 4, t^2 + t + 1)$ lies on the line x + 2y = 1 for

• A. all real values of t
• B. some real values of t
• C. $t = \frac{ - 4 \pm \sqrt{7}}{8}$
• D. no real values of t

Answer 1

Answer: (D)

no real values of t

Answer 2

sub given point in given equation