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Physics Question on Resistance

The plate resistance of a triode is 3×103Ω3 \times 10^3 \Omega and its mutual conductance is 1.5×10−3A/V1.5 \times 10^{-3} A/V. The amplification factor of the triode is

A

5×10−55 \times 10^{-5}

B

4.5

C

45

D

2×1052 \times 10^5

Answer

4.5

Explanation

Solution

Given, rp=3×103 Ω,gm=1.5×10−3A/Vr_p = 3 \times 10^3 \, \Omega, g_m = 1.5 \times 10^{-3} A/V
∴\therefore Amplification factor, μ=gm×rp=4.5\mu = g_m \times r_p = 4.5
thereforetherefore Correct option is (b).