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Question

Physics Question on Electricity

The plane 𝑧=0 separates two linear dielectric media with relative permittivities πœ€π‘Ÿ1=4 and πœ€π‘Ÿ2=3, respectively. There is no free charge at the interface. If the electric field in the medium 1 is 𝐸⃗ 1=3π‘₯Μ‚+2𝑦̂ +4𝑧̂, then the displacement vector D2β†’\overrightarrow{D_2} in medium 2 is: (πœ€0 is the permittivity of free space)

A

(3π‘₯Μ‚ + 4𝑦̂ + 6𝑧̂)πœ€0

B

(3π‘₯Μ‚ + 6𝑦̂ + 8𝑧̂)πœ€0

C

(9π‘₯Μ‚ + 6𝑦̂ + 16𝑧̂)πœ€0

D

(4π‘₯Μ‚ + 2𝑦̂ + 3𝑧̂)πœ€0

Answer

(9π‘₯Μ‚ + 6𝑦̂ + 16𝑧̂)πœ€0

Explanation

Solution

The correct option is (C): (3π‘₯Μ‚ + 6𝑦̂ + 8𝑧̂)πœ€0