Solveeit Logo

Question

Physics Question on spherical lenses

The plane face of a planoconvex lens is silvered. If μ\mu be the refractive index and RR, the radius of curvature of curved surface, then the system will behave like a concave mirror of radius of curvature

A

μR\mu R

B

R(μ1)\frac{R}{(\mu - 1)}

C

Rμ\frac{R}{\mu}

D

[(μ+1)(μ1)]R\left[\frac{\left(\mu+1\right)}{\left(\mu-1\right)}\right]R

Answer

R(μ1)\frac{R}{(\mu - 1)}

Explanation

Solution

For planoconvex lens (without its plane surface silvered),
1fL=(μ1)(1R1)=μ1R\frac{1}{f_{L}} =\left(\mu-1\right)\left(\frac{1}{R}-\frac{1}{\infty}\right)=\frac{\mu-1}{R}
or fL=R(μ1)f_{L}=\frac{R}{\left(\mu-1\right)}
When an object is placed in front of the planoconvex lens with its plane face silvered, light rays are : (i) refracted at the convex surface (ii) reflected at the silvered surface and (iii) refracted again at convex surface. If FF is the effective focal length of the combination, then
1F=1fL+1fM+1fL=2fL\frac{1}{F} =\frac{1}{f_{L}}+\frac{1}{f_{M}}+\frac{1}{f_{L}}=\frac{2}{f_{L}} (as fM=8 f_M = 8)
or F=fL2=R2(μ1)F =\frac{f_{L}}{2}=\frac{R}{2\left(\mu-1\right)}
\therefore Radius of curvature of the concave mirror
=2F=(Rμ1)= 2F =\left(\frac{R}{\mu-1}\right)