Question
Question: The plane containing the two lines \(\frac{x - 3}{1}\)= \(\frac{y - 2}{4}\) = \(\frac{z - 1}{5}\) an...
The plane containing the two lines 1x−3= 4y−2 = 5z−1 and 1x−2 = −4y+3 = 5z+1 is 11x + my + nz = 28 where-
A
m = –1, n = 3
B
m = 1, n = –3
C
m = –1, n = –3
D
m = 1, n = 3
Answer
m = –1, n = –3
Explanation
Solution
Point (3, 2, 1) & (2, –3, –1)
lies on 11x + my + nz = 28
i.e., 33 + 2m + n = 28
Ž 2m + n = –5 … (1)
and 22 – 3m – n = 28
Ž –3m – n = 6 … (2)
From (1) and (2)
m = –1 & n = –3.