Question

The plane $2x−y+z=4$ intersects the line segment joining the points $A(a,−2,4)$ and $B(2,b,−3)$ at the point C in the ratio $2:1$ and the distance of the point C from the origin is $\sqrt5$. If $ab<0$ and $P$ is the point $(a−b,b,2b−a)$. Then $CP^2$ is equal to

• A. $\frac{16}{3}$
• B. $\frac{17}{3}$
• C. $\frac{73}{3}$
• D. $\frac{97}{3}$

Answer 1

Answer: (B)

$\frac{17}{3}$

Answer 2

The Correct Option is (B): $\frac{17}{3}$