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Question

Physics Question on Dimensional Analysis

The physical quantity having the dimensions [M1L3T3A2]\left[ M ^{-1} L ^{-3} T ^{3} A ^{2}\right] is

A

resistance

B

resistivity

C

electrical conductivity

D

electromotive force

Answer

electrical conductivity

Explanation

Solution

Resistivity, ρ=mne2τ\rho=\frac{m}{n e^{2} \tau} [ρ]=[M][L3][AT]2[T]\because [\rho] =\frac{[ M ]}{\left[ L ^{-3}\right][ AT ]^{2}[ T ]} =[ML3A2T3]=\left[ ML ^{3} A ^{-2} T ^{-3}\right] So, electrical conductivity, σ=1ρ\sigma=\frac{1}{\rho} [σ]=1[ρ]=[M1L3A2T3]{[\sigma]=\frac{1}{[\rho]}=\left[ M ^{-1} L ^{-3} A ^{2} T ^{3}\right]}