Question

The photograph of a house occupies an area of 1.75 $\text{cm}^2$ on a 35 mm slide. The slide is projected on to a screen, and the area of the house on the screen is 1.55 $\text m^2$. What is the linear magnification of the projector-screen arrangement.

Answer 1

Area of the house on the slide = 1.75 $\text{cm}^2$
Area of the image of the house formed on the screen = 1.55 $\text m^2$
= 1.55 × $10^4$ $\text{cm}^2$
Arial magnification, ma =$\frac{\text{ Area of image }}{\text{ Area of object }}$= $\frac{1.55}{1.75} \times 10^4$
$\therefore$ Linear magnifications, ml =$\sqrt{m_a}$
=$\sqrt{ \frac{1.55 }{ 1.75 }× 10^4}$ = 94.11