Solveeit Logo

Question

Question: The photoelectric threshold frequency of a metal is U . When light of frequency \(40\) is incident...

The photoelectric threshold frequency of a metal is U . When light of frequency 4040 is incident on the metal, The maximum kinetic energy of the emitted photoelectron is :

A

4ho

B

C

5ho

D

5hv2\frac { 5 h v } { 2 }

Answer

Explanation

Solution

: the maximum kinetic energy of the emitted electron is given by

Kmax=hvϕ0=h(4v)h(v)=3hvK _ { \max } = h v - \phi _ { 0 } = h ( 4 v ) - h ( v ) = 3 h v