Question

The photoelectric cut off voltage in a certain experiment is $1.5\, V$. The maximum kinetic energy of photoelectrons emitted is

• A. $2.4\,eV$
• B. $1.5\,eV$
• C. $3.1\,eV$
• D. $4.5\,eV$

Answer 1

Answer: (B)

$1.5\,eV$

Answer 2

Here, $V_{0}=1.5\,V$, Maximum kinetic energy $=eV_{0}=1.5\,eV$