Question

The photoelectric cut off voltage in a certain experiment is 1.5V. the maximum kinetic energy of photoelectrons emitted is :

• A. 2.4 eV
• B. 1.5 eV
• C. 3.1 eV
• D. 4.5 eV

Answer 1

Answer: (B)

1.5 eV

Answer 2

: Here $V_{0} = 1.5V$

Maximum kinetic energy

$= eV_{0} = 1.5eV$