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Question

Physics Question on Wave characteristics

The phase velocity of a wave described by the equation Ψ=Ψ0sin(kx+ωt+π/2)\Psi = \Psi_0 \, \sin (kx + \omega t + \pi / 2) is

A

xt\frac{x}{t}

B

Ψ0ω\frac{\Psi_0 } { \omega}

C

ωk\frac{\omega}{k}

D

π2k\frac{\pi} {2k}

Answer

ωk\frac{\omega}{k}

Explanation

Solution

Given,
ψ=ψ0sin(kx+ωt+π2)\psi=\psi_{0} \sin \left(k x+\omega t+\frac{\pi}{2}\right)
Phase velocity of wave
V=ωk= Angular frequency  Propagation constant V=\frac{\omega}{k}=\frac{\text { Angular frequency }}{\text { Propagation constant }}