Question

The phase difference between two waves, represented by y1 = 10–6 sin {100t + ($\frac{x}{50}$) + 0.5}m y2 = 10–6 cos{100t + ($\frac{x}{50}$)}m Where X is expressed in meters and t is expressed in seconds, is approximately

• A. 2.07 radians
• B. 0.5 radians
• C. 1.5 radians
• D. 1.07 radians

Answer 1

Answer: (D)

1.07 radians

Answer 2

The phase difference between the two waves is approximately 1.07 radians.