Question

The phase difference between the two particles situated on both the sides of a node is

• A. 0°
• B. 90°
• C. 180°
• D. 360°

Answer 1

Answer: (C)

180°

Answer 2

Both the sides of a node, two antinodes are present with separation $\frac{\lambda}{2}$ So phase difference between then

$\varphi = \frac{2\pi}{\lambda} \times \frac{\lambda}{2} = \pi$